Question

Divide a rope of length 80 m into two parts,such that one part exceeds the other by 20 m.​

Answer 1

Answer:

Step-by-step explanation:

Let the required length of first part be x

Hence second part=20+x

Total length=80

So ATQ

20+x +x= 80

2x=60

X=30

And second part=20+30=50