Question

Divide as instructed 20 (y+4) (y^2+5y+3) ÷ 5 (y+4)​

Answer 1

Step-by-step explanation:

$20(y+4)(y ^ { 2 } +5y+3) \div 5(y+4) \\ \frac{\left(20y+80\right)\left(y^{2}+5y+3\right)}{5}\left(y+4\right) \\ \frac{20y^{3}+180y^{2}+460y+240}{5}\left(y+4\right) \\ \frac{\left(20y^{3}+180y^{2}+460y+240\right)\left(y+4\right)}{5} \\ \frac{20y^{4}+260y^{3}+1180y^{2}+2080y+960}{5}$

$4y^{4}+52y^{3}+236y^{2}+416y+192$