Question

divide ax^2+(b+ac)x+bc by x+c

Answer 1

x+c }ax²+(b+c)x+bc{ ax + (b+c) - ac
ax²+ axc
—————
(b+c)x-axc +bc
(b+c)x+(b+c)c
———————
-axc+bc-bc-c²
-axc-ac²
————————
ac²-c²= c²(a-1)