if alpha nd beta are roots of the quadratic equation x2 -x+ p=0 and aldpa Square nd beta square =3 then find the value of p
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alpha + beta = 1 -------(1)
alpha.beta = P -----(2)
now,
alpha² - beta² = ( alpha - beta )( alpha + beta ) = ( alpha -beta ) .1
=( alpha -beta ) = 3
√{( alpha+ beta)² -4alpha.beta } = 3
( 1 )² -4P = 9
P = 2
alpha.beta = P -----(2)
now,
alpha² - beta² = ( alpha - beta )( alpha + beta ) = ( alpha -beta ) .1
=( alpha -beta ) = 3
√{( alpha+ beta)² -4alpha.beta } = 3
( 1 )² -4P = 9
P = 2
hks2:
thank you
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