Divide first polynomial by the second polynomial by synthetic division and find the remainder 2x³-3x²+4x-5; X+3
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2x( ki p 3) - 3x( ki p 2) + 4x - 5 , x+3
p(x) = 2x( ki p 3) - 3x( ki p 2) + 4x - 5
p( x) = x+3 = 0
p(x)= x= 0-3
p( x) = x= -3
p(-3) = 2(-3) [ ki p 3) - 3(-3) [ ki p 2) + 4(-3) - 5
p(-3) = -54( ki p 3) - 27( ki p 2) + 12 - 5
p(-3) = -54( ki power 3 ) - 27( ki power 2 ) + 7
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