Question

DIVIDE
(ii) 1 + y^3 by 1 + y
​

Answer 1

$\frac{ {y}^{3} + 1 }{y + 1} \\ = \frac{(y + 1)( {y}^{2} - y + 1) }{y + 1} \\ = {y}^{2} - y + 1$

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