Question

Divide (p 2 q 2 r 5 - p3q5x2 + p5q3x2) ÷ p2q2r2​

Answer 1

$\frac{p^{2}q^{2}r^{5}-p^{3}q^{5}x^{2}+p^{5}q^{3}x^{2}}{p^{2}q^{2}r^{2}}$

$= \frac{p^{2}q^{2} ( r^{5}-pq^{3}x^{2}+p^{3}qx^{2})}{p^{2}q^{2}r^{2}}\\= \frac{( r^{5}-pq^{3}x^{2}+p^{3}qx^{2})}{r^{2}}$

Therefore.,

$\red {\frac{p^{2}q^{2}r^{5}-p^{3}q^{5}x^{2}+p^{5}q^{3}x^{2}}{p^{2}q^{2}r^{2}}}$

$\green { = \frac{( r^{5}-pq^{3}x^{2}+p^{3}qx^{2})}{r^{2}}}$

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