Math, asked by Harshrock876, 10 hours ago

Divide R100 between A and B so that ¾ of what B gets is R5 more than the amount A receives

Answers

Answered by bagkakali
0

Answer:

let B gets Rs x

so, A gets Rs (100-x)

3x/4-5=(100-x)

=> 3x/4=100-x+5

=> 3x/4=105-x

=> 3x=4(105-x)

=> 3x=420-4x

=> 3x+4x=420

=> 7x=420

=> x=420/7

=> x=60

so, B gets Rs 60 and A gets Rs (100-60)=Rs 40

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