Math, asked by anshkumarp510, 9 months ago

Divide Rs. 13000 into two parts in such a manner that the simple interest on the first part for 3 years at 5% per annum remains equal to two times the simple interest on the second part for 4 years at 3% per annum. Then the second part of amount after 2 year is??

Answers

Answered by mhanifa
10

Answer:

₹5300

Step-by-step explanation:

Total sum - ₹13000

First part - x

Total Interest in first part= x*0.05*3

Total interest in second part= (13000-x)*0.03*4

------------------

So, the interest in first part is 2 times more than the the interest in second part:

  • x*0.05*3=2*(13000-x)*0.03*4
  • 0.15x=0.24(13000-x)
  • 0.15x+0.24x= 3120
  • 0.39x=3120
  • x=3120/0.39
  • x= ₹8000 first part

Second part= ₹13000-₹8000= ₹5000

Then the second part of amount after 2 year is:

  • ₹5000+2* ₹5000*0.03= ₹5300

Hope it helps

Similar questions