Question

divide rs.3010 among A B C in such a way that A gets double of what B gets and B gets double of what C gets

Answer 1

Step-by-step explanation:

A gets Rs 1720

B gets Rs 860

C gets Rs 430

Let A get Rs a

B get Rs b

and, C get Rs c.

Total money to be divided amongst A, B and C = Rs 3010

So, a + b + c = 3010         ...(1)

Also, A gets double of what B gets, so we can represent this statement as:

a = 2b                                  ...(2)

And, B gets double of what C gets, again we can represent it as:

b = 2c

⇒c = b/2                              ...(3)

Substituting the value of a = 2b (from eqn. (2)) and c = b/2 (from eqn. (3)), in eqn. (1), we get:

2b + b + b/2 = 3010

⇒7b/2 = 3010

⇒ b = (3010×2)÷7 = Rs 860

So, B gets Rs 860.

Putting the value of b in eqn. (2), we get the value of a as:

a = 2b = 2×860 = Rs 1720

Again, putting the value of b in eqn. (3), we get the value of c as:

c = b/2 = Rs (860/2) = Rs 430

Answer 2

Given :-

• Total amount distributed among A, B & C = Rs. 3010
• Total amount A gets = twice the amount B gets.
• Total amount B gets = twice the amount C gets.

To Find :-

• Total amount A, B & C will get separately.

Solution :-

Suppose Rs. x be the total amount C will get. Then,

• Total amount B will get = Rs. 2x (twice the amount of C).
• Total amount A will get = Rs. 4x (twice the amount of B).

According to the question,

⇒ 4x + 2x + x = 3010

⇒ 7x = 3010

⇒ x = 3010/7

⇒ x = 430

Therefore, C will get Rs. 430.

Also,

• B will get = Rs. 860 ( 2 × 430)
• A will get = Rs. 1720 ( 2 × 860)