Question

divide rs 47 between A , B and C so that A may have rs 10 more than B and B have rs 8 more than C .​

Answer 1

Step-by-step explanation:

A=b+10 ,B=C+8

A . T . Q .

A +B+C=47

b+10+c+8+c=47

b+18+2c=47

b+2c = 47-18

b+2c =29

As we know b =c+10

therefore, c+10+2c=29

3c+10=27

3c = 29-10

3c =17

c = 17/3

Answer 2

let C gets rs x.

so B gets rs = x+8

and A gets rs = x+8+10

now, A+B+C = ₹47

or, x+x+8+x+10 = ₹47

or, 3x+18 = ₹47

or, 3x = ₹47- ₹18

or, 3x = ₹29

thus, x= 29/3

C = 29/3 = 9.66

B = 29/3+8 = 53/3 = 17.66

A = 17.6 + 10 = 27.66