Question

divide rs 500 in the ratio 3:6:11.

Answer 1

Let the common multiple be x.
so 3x:6x:11x is the ratio.
Sum of the distributions = 500
3x + 6x+ 11x = 500
20x = 500
x = 25
First distribution = 3x = 75
Second distribution = 6x = 150
Third distribution = 11x = 225.

hope this helps.......

Answer 2

Sum of the ratios = 3+ 6 + 11 = 20
Now :- 1st (3 will get) = 3/20 × 500 = 75
2nd (6 will get) = 6/20×500 = 150
3rd (11 will get) = 11/20 ×500 = 275
Therefore 3 will get rupees 75
6 will get rupees 150 and
11 will get rupees 275