Math, asked by DSTAR3420, 10 months ago

Divide rs. 680 among p, q, and r such that p gets 2/3 of what q gets and q gets 1/4 of what r gets. Find the share of r.

Answers

Answered by loki3000
31

Answer:

let r get x

q will get x/4

p will get x / 6

x + x/4 + x/6 = 680

680 *12 = 12x + 3x + 2x

680*12 = 17x

x = 680/17*12

x= 40*12

x = 480

r = ₹480

q = ₹120

p = ₹80

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Answered by JeanaShupp
12

Answer: The share of r is Rs. 480

Step-by-step explanation:

Let the share of r = x

According to question

q gets = Rs.\dfrac{1}{4} x

p gets = \dfrac{2}{3}\times \dfrac{1}{4}x=Rs. \dfrac{x}{6}

Total money is Rs. 680

Therefore

680 = x+ \dfrac{x}{4} +\dfrac{x}{6}\\\\\Rightarrow 680 = \dfrac{12x+ 3x+2x}{12}\\\\\Rightarrow 680\times 12= 17x\\\\\Rightarrow x= Rs. 480

Hence, the share of r is Rs. 480

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