Question

Divide rs1312 into three parts such that first part is 2/3 of the second and the ratio between second and third part is 4:7 .​

Answer 1

Answer:

x+y+z=1312...(1)

x= (2/3) y

(y/z)=(4/7)

y= (4/7)z

x= (2/3)×(4/7)z=(8/21)z

put the values of these x and y in eqn (1)

(8/21)z + (4/7)z +z =1312

(41/21)z = 1312

z = 1312×21/41 = 672

y = (4/7)×z = (4/7)×672=384

x = (8/21)z = (8/21)×672=256

Ans: 256, 384, 672