Question

divide rupees 3740 in three parts in such a way that half of the first part one third of the second part and one sixth of the third part are equal

Answer 1

let 1st part be a,
2nd part be b,
3rd part be c

now given
1/2a=1/3b=1/6c let it be equal to some constant-k
then,
a=2k
b=3k
c=6k
total = 11k=3740
implies k= 340

so 1st part is a= 680
2nd part is b= 1020
3rd part is C= 2040.