Question

Divide rupees 47 among A,B and C so that A may have rupee 10 more than B and B has rupee 8 more than C.

Answer 1

let c=x
so,47=a+b+c
47=x+{x+8}+(x+8)+10
because it is given that c+8=b and b+10 =a
47=3x+26
3x=21
x=7

so,c=7
b=7+8=15
a=15+10=25

Answer 2

Lets take B share to be x
So,
A=10+x
C=x-8
Therefore,
x+10+x+x-8=47
3x+2=47
3x=47-2
x=45/3
x=15
According to the question
A=10+15=Rs 25
B=Rs 15
C=15-8=Rs 7