Math, asked by nehaverma4544, 1 year ago

divide rupees 500, A,B,C,D so that A and B together gets thrice as much as C and D together, B gets four times of what C gets in C gets 1.5 times as much as D. now the value of what B gets is ​

Answers

Answered by study20098
0

Step-by-step explanation:

given A+B:C+D=3:1

A+B)'s share 4 = Rs.500×34 =Rs.375

(C+D)'s share = Rs.500×14 = Rs.125

C : D = 32 : 1 (given)

= 3 : 2

C's share = Rs.125×35 = Rs.75

D's share = Rs.125×25 = Rs.50

B's share = Rs.75×4=Rs.300

Answered by throwdolbeau
0

Answer:  

Share of B = Rs. 300

Step-by-step explanation:

Given that A and B together get thrice as much as C and D together

⇒ (A + B) = (C + D) = 3 : 1

Total money which is to be distributed = Rs 500

Share of (A + B) = 3/4 × 500 = Rs. 375

Share of (C + D) = 1/4 × 500 = Rs. 125

Now, C gets 1.5 times as much as D

⇒ C + D = 125

⇒ 1.5 D + D = 125

⇒ 2.5 D = 125

⇒ Share of D = Rs. 50

So, Share of C = 125 - 50  

                        = Rs. 75

Also, B gets four times of what C  gets

⇒ Share of B = 75 × 4

                       = Rs. 300

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