Question

Divide rupees 715 among A B and C in such a way that B gets three times as much as A gets and C gets half of as much as B gets.​

Answer 1

Step-by-step explanation:

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Answer 2

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Given:

• 715 Rs is divided among A, B and C
• B gets three times as much as A gets
• C gets half as much as B gets

To find:

How much A, B and C gets = ?

Solution:

B gets three times as much as A gets,

So, the equation becomes,

B = 3A ---(1)

C gets half as much as B gets

So, the equation we get becomes,

C = B/2 ----(2)

Substituting value of B in equation (2)

C = 3A/2 ---(3)

On adding,

A + B + C = 715

$\\ \\ A + 3 A + \dfrac{3A}{2} = 715 \\ \\ 4A + \dfrac{3A}{2} = 715 \\ \\ \dfrac{8A + 3A}{2} = 715$

$\\ \\ \dfrac{11A}{2} = 715 \\ \\ 11A = 715 \times 2 \\ \\ 11A = 1430 \\ \\ A = \dfrac{1430}{11}$

$\\ A = 130$

Substituting value of A in equation (1)

B = 3A

B = 3 × 130

B = 390

Substituting value of A in equation (3)

C = 3A/2

C = 3 × 130/2

C = 390/2

C = 195

Answer:

Thus, A got Rs 130, B got Rs 390 and C got

Rs 195

Verification:

If value of A, B and C equals to 715 our answer is correct

A + B + C = 715

130 + 390 + 195 = 715

715 = 715

LHS = RHS

Basic point:

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