Question

Divide
$2x square + 1 \: by + x - 17$
By Long Division​


Pls answer it fast


Answer well

Answer 1

Step-by-step explanation:

Here, p(x) = 2x^2 + 1

g(x) = x - 17

q(x) = 2x

r(x) = 35

How you may find the first term of Quotient?

It's lot simpler than you think. Just we've to divide the first term of dividend by the first term of divisor.

Here, $\frac{2x^2}{x} = 2x$

Then multiply that term with all the terms and write them below each term with respect to their power.

Then subtract each term. In the attachment, you may have seen that, I've changed sign of each term. As we know, will subtracting, we've to change its sign when minus sign is outside the bracket.

We may see it horizontally as,

2x^2 - (2x^2) = 2x^2 - 2x^2 = 0

We have to stop the division of polynomials when : -

1. When the remainder is zero.
2. When the degree of the remainder is lesser than the dividend.

Here, 35's degree is 0, which we can write it as,

35x^0 = 35(1) = 35 [since, x^0 = 1]

Since, the degree is lesser than the divisor so we've to stop the division here!

Answer 2

R(x)=35 is answer for your question