divide
![divide(x3 - 6x2 + 11x - 6) \: byx - 3using \:the \: factorization \: method divide(x3 - 6x2 + 11x - 6) \: byx - 3using \:the \: factorization \: method](https://tex.z-dn.net/?f=divide%28x3+-+6x2+%2B+11x+-+6%29+%5C%3A+byx+-+3using+%5C%3Athe+%5C%3A+factorization+%5C%3A+method)
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Answered by
30
Step-by-step explanation:
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Answered by
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→ Refer the attachment for solution.
Explanation :-
First of all, Divide ( x³ - 6x² + 11x - 6 ) by
( x - 3 ).
You will get :- x² - 3x + 2
Now,
Factorise x² - 3x + by by splitting the middle term, i.e 3x
= x² - ( 2 + 1 )x + 2
After solving this, you will get ( x - 1 ) and ( x - 2 )
So,
Finally, we have got the answer, i.e
( x - 3 ) ( x - 1 ) ( x - 2 )
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