Question

Divide the following by method of factorization 66(y^4 - 5y^3 - 24y^2) ÷ 6y ( y-8)​

Answer 1

Answer:

(((y4)-(5•(y3)))-(23•3y2))

((66•——————————————————————————)•y)•(

(((y4)-5y3)-(23•3y2))

((66•—————————————————————)•y)•(y-8)

6

y4 - 5y3 - 24y2

Simplify ———————————————

6

Pull out like factors :

y4 - 5y3 - 24y2 = y2 • (y2 - 5y - 24)

y2•(y+3)•(y-8)

((66•——————————————)•y)•(y-8)

6

(11y2 • (y + 3) • (y - 8) • y) • (y - 8)

y2 multiplied by y1 = y(2 + 1) = y3

11y3 • (y + 3) • (y - 8) • (y - 8)

In our case, the common base is (y-8) and the exponents are :

In our case, the common base is (y-8) and the exponents are : 1 , as (y-8) is the same number as (y-8)1

In our case, the common base is (y-8) and the exponents are : 1 , as (y-8) is the same number as (y-8)1 and 1 , as (y-8) is the same number as (y-8)1

In our case, the common base is (y-8) and the exponents are : 1 , as (y-8) is the same number as (y-8)1 and 1 , as (y-8) is the same number as (y-8)1 The product is therefore, (y-8)(1+1) = (y-8)2

Answer: 11y3 • (y + 3) • (y - 8)2