Question

divide the following by middle term splitting : x²+11x+18​

Answer 1

${x}^{2} + 11x + 18$

${x}^{2} + (9 + 2)x + 18$

${x}^{2} + 9x + 2x + 18$

$x(x + 9) + 2(x + 9)$

$(x + 9)(x + 2)$

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Answer 2

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=》 x² + 11x + 18.

☆ So,

▪︎To split middle term let us find the primes of 18,

${\large{\blue{\boxed{\bold{=\:2×3×3}}}}}$

▪︎ Also,

=》 2 + (3×3).

= 2 + 9.

${\large{\blue{\boxed{\bold{=\:11.}}}}}$

= Middle term.

☆ Therefore,

Let us spilt the middle term,

=》 x² + 11x + 18.

= x² + (9+2)x + 18.

= x²+9x+2x+18.

= x(x+9) + 2(x+9)

${\large{\orange{\boxed{\bold{=\:(x+2)\:(x+9).}}}}}$

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