divide the following iv). 28(x + 3) (x2 + 3x + 7) = 7(x + 3)
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28(x+3)(x2+3x+7)=7(x+3)
28x3+168x2+448x+588=7x+21
Step 1: Subtract 7x+21 from both sides.
28x3+168x2+448x+588−(7x+21)=7x+21−(7x+21)
28x3+168x2+441x+567=0
Step 2: Factor left side of equation.
7(x+3)(4x2+12x+27)=0
Step 3: Set factors equal to 0.
x+3=0 or 4x2+12x+27=0
x=−3
Answer:
x=−3
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