Question

divide the following iv). 28(x + 3) (x2 + 3x + 7) = 7(x + 3)​

Answer 1

28(x+3)(x2+3x+7)=7(x+3)

28x3+168x2+448x+588=7x+21

Step 1: Subtract 7x+21 from both sides.

28x3+168x2+448x+588−(7x+21)=7x+21−(7x+21)

28x3+168x2+441x+567=0

Step 2: Factor left side of equation.

7(x+3)(4x2+12x+27)=0

Step 3: Set factors equal to 0.

x+3=0 or 4x2+12x+27=0

x=−3

Answer:

x=−3