Math, asked by Jayant925user, 9 months ago

Divide the following monomial by given monomial √2y^3 by 3√2y^2

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Answered by itzankit21
3

Answer:

6x) ÷ 3x (ii) (3y^8 − 4y^6 + 5y^4) ÷ y^4 (iii) 8(x^3y^2z^2 + x^2y^ 3z^2 + x^2y^2z^3) ÷ 4x^2y^2z^2 (iv) (x^3 + 2x ^ ...

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