Math, asked by lipsajena00000, 2 days ago

divide the following polynomial by the given monomial and hence find quotient (a) 3m^2n^3- 2mn^2+ 15mn by 3 mn​

Answers

Answered by mandeepkaur1980mk
0

Step-by-step explanation:

Given

3mn

3m

2

n

3

−2mn

2

+15mn

/* Divide each term by 3mn , we get */

= \frac{3m^{2}n^{3}}{3mn} - \frac{2mn^{2}}{3mn} + \frac{15mn}{3mn}=

3mn

3m

2

n

3

3mn

2mn

2

+

3mn

15mn

= \frac{3mn \times mn^{2}}{3mn} - \frac{mn \times 2n}{3mn} + \frac{3mn\times 5}{3mn}=

3mn

3mn×mn

2

3mn

mn×2n

+

3mn

3mn×5

= mn^{2} - \frac{2}{3} n + 5=mn

2

3

2

n+5

Therefore.,

\red {\frac{3m^{2}n^{3} - 2mn^{2} + 15mn}{3mn}}

3mn

3m

2

n

3

−2mn

2

+15mn

\green { =mn^{2} - \frac{2}{3} n + 5}=mn

2

3

2

n+5

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