Question

Divide the following polynomials by monomial ​

Answer 1

Answer:

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Answer 2

The answer of this question is $- [q^{2}+2q+\frac{1}{2\sqrt{2} } ]$.

Step-by-step explanation:

We are given a polynomial ,

$2\sqrt{2}q^{4}+4\sqrt{2}q^{3}+q^{2}$

and a monomial,

$-2\sqrt{2} q^{2}$

We have to find the answer of the division of polynomial by the monomial such as,

$\frac{2\sqrt{2}q^{4}+4\sqrt{2}q^{3}+q^{2}}{-2\sqrt{2} q^{2} }$

• Solving the division,

for solving this question first we take common $2\sqrt{2} q^{2}$ from numerator as,

$2\sqrt{2} q^{2}[q^{2}+2q+\frac{1}{2\sqrt{2} } ]$

now divide this new numerator to the denominator we get,

$\frac{2\sqrt{2} q^{2}[q^{2}+2q+\frac{1}{2\sqrt{2} } ]}{-2\sqrt{2} q^{2} }$

cancel out the $2\sqrt{2} q^{2}$  from numerator and denominator, then we get a simple quadratic equation,

$- [q^{2}+2q+\frac{1}{2\sqrt{2} } ]$

so we get our answer as $- [q^{2}+2q+\frac{1}{2\sqrt{2} } ]$.