Divide the following polynomials by trinomials.
(a) x^4+ 4x^3 + x – 10 by x^2+3x-5
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(c) -1
Let f(x) = ax3 + 4x2 + 3x – 4
g(x) = x3 – 4x + a.
Remainders when f(x) and g(x) are divided by (x – 3) are f(3) and g(3) respectively. Now,
f(3) = a. (3)3 + 4.(3)2 + 3.3 – 4
= 27a + 36 + 9 – 4 = 27a + 41 ...(i)
g(3) = (3)3 – 4.(3) + a = 27 – 12 + a = 15 + a ...(ii)
Given, f(3) = g(3)
∴ 27a + 41 = 15 + a ⇒ 26a = – 26 ⇒ a = – 1.
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