Divide the following
(x3+2x2+3x) ÷2
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( x³ + 2x² + 3x )/2x
=> [ x ( x² + 2x + 3 ) ]/2x
=> ( x² + 2x + 3 )/2
=> x²/2 + 2x/2 + 3/2
=> x²/2 + x + 3/2.
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