Question

divide the given polynomial by the given monomial (p3q6−p6q3)÷p2q2
​

Answer 1

Answer:

The solution of

$({p}^{3} {q}^{6} - {p}^{6} {q}^{3}) \div {p}^{2} {q}^{2}$

is

$p {q}^{4} - {p}^{4} q$

Step-by-step explanation:

If we have to divide

$({p}^{3} {q}^{6} - {p}^{6} {q}^{3})$

by

${p}^{2} {q}^{2}$

we have to go through the following steps:

Step 1: Cancelling the first term by multiplying the monomial divisor by

${p} {q}^{4}$

${p}^{2} {q}^{2} \times p {q}^{4} = {p}^{3} {q}^{6}$

$({p}^{3} {q}^{6} - {p}^{6} {q}^{3}) - {p}^{3} {q}^{6} = {p}^{6} {q}^{3}$

Step 2: Cancel the second term by multiplying the monomial divisor by

${p}^{4} q$

${p}^{2} {q}^{2} \times {p4}^{q} = {p}^{6} {q}^{3}$

${p}^{6} {q}^{3} - {p}^{6} {q}^{3} = 0$

So,

${p}^{2} {q}^{2} \times (p {q}^{4} - {p}^{4} q) = {p}^{3} {q}^{6} - {p}^{6} {q}^{3}$