divide the mumber 20 into two parts such that their product is maximum.
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Let one part = x
other part = (20-x)
their product, p = x(20-x) = 20x - x²
For the product, p to be maximum
So, product is maximum when we divide 20 into 2 parts as (10,10).
Note: If you want to show that dividing 20 into (10,10) yield
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