heyy Guyzz plz help me with this
IF AN ANGLE IS 30°MORE THAN ONE HALF OF ITS COmpLEMENT FIND THE MEAUSRE OF THE ANGLE
want full explanation no spamm
abhiraj03:
Hi cat
Answers
Answered by
6
Let us assume that the angle is x.
Then,its complement will be 90-x.
30 degree more than one half of its complement, i.e 30+(90-x)/2
According to the sum,
x=30+(90-x)/2
x=60+90-x/2
x=150-x/2
2x=150-x
3x=150
x=50.
Hence the angle is 50.
Then,its complement will be 90-x.
30 degree more than one half of its complement, i.e 30+(90-x)/2
According to the sum,
x=30+(90-x)/2
x=60+90-x/2
x=150-x/2
2x=150-x
3x=150
x=50.
Hence the angle is 50.
Answered by
4
let one angle be x
the compliment will be 90-x
half the compliment = 1/2 * (90-x)
x = 1/2*(90-x)+30
x =1/2 *90 - 1/2 *x +30
x =45 -1/2 *x +30
3x/2 = 75
3x = 150
x=50
the compliment will be 90-x
half the compliment = 1/2 * (90-x)
x = 1/2*(90-x)+30
x =1/2 *90 - 1/2 *x +30
x =45 -1/2 *x +30
3x/2 = 75
3x = 150
x=50
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