Math, asked by NilotpalSwargiary, 11 months ago

Divide the number 18 into two positve parts so that the sum of their
squares is equal to 15 times of the larger part.​

Answers

Answered by MukulCIL
5

Answer:

there are two pairs of answers, sinche it is not mentioned whether the numbers will be integer or not.

18= 13.5 + 4.5

OR

18= 12 + 6

Step-by-step explanation:

let x + y = 18

given

x^2 + y^2 = 15y

Now put x = 18-y in above equation

324+ y^2-36y + y^2 = 15y

2y^2 -51y +324 = 0

2y^2 -24y -27 y +324 = 0

(2y- 27)(y-12) = 0

y= 13.5, y= 12

Answered by crystalch24092
11

Let the two positive parts in which number 18 can be divided be x and y ,where x is the larger part.

Such that, the sum of their squares is equal to 15 times the larger part.

Then, x + y = 18

x² + y² = 15x

Please , check the attachment for the solution.

Hope this helped you..

Attachments:
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