Divide the polynomial 3x^4-3-3x-1 by x-1.write quotient and remainder.
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p(x)=3x^4-3-3x-1
g(x)=x-1=0
x=0+1
x=1
p(x)=3x^4-3-3x-1=0
p(1)=3*1^4-3-3*1-1
p(1)=3-3-3-1
p(1)=-4
remainder=-4
g(x)=x-1=0
x=0+1
x=1
p(x)=3x^4-3-3x-1=0
p(1)=3*1^4-3-3*1-1
p(1)=3-3-3-1
p(1)=-4
remainder=-4
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