Question

Divide the polynomial 9x3-3x2 + 15x-3 by (x-1) and find its quotient and
remainder.​

Answer 1

9x^3-3x^2 + 15x-3 ÷ x-1

Answer 2

Given: divide $9x^3-3x^2+15x-3$ by (x-1)

To find: quotient and  remainder.​

Step-by-step explanation:

In early algebra, the expression of several terms related to plus (+) and minus (-) signs is called polynomial, according to the number of terms its specific surname 'monomial', 'binomial' (binomial). ), Etc. In higher mathematics, polynomial is typically used for an expression whose terms contain zero or plus integer powers of any one variable amount, or more than one variable, in ascending or descending order.

According to question

$f(x)=9x^3-3x^2+15x-3$

$g(x)=x-1$

$Dividend = Divisor \times Quotient+Remainder$

Divide $9x^3-3x^2+15x-3$ by $x-1$  (Solution is given in the figure)

After solving, we get,

Quotient = $9x^2+6x+21$ and remainder = 18