Question

divide the polynomial(a^2+7a+10)divide(a+5)​

Answer 1

Answer:

0

Explanation:

By long division method,

${\begin{array}\quad\begin{tabular}{m{3.5em}cccc}&& a& + 2&\\\cline{3-5}\multicolumn{2}{l}{a+ 5\big)}& \not{a^{2}}& + 7a & + 10 & \\&& \not{a^{2}}&+5a&&\\&&(-)&(-) &&\\ \cline{3-5}&&& \not{2a}& + \not{10}& \\&&& \not{2a}& + \not{10} &\\ &&&(-)&(-)&\\ \cline{4-5}&&&& 0& \\ \cline{4-6}\\ \\\end{tabular}\end{array}$

Therefore,

When a^2+7a+10 is divided by a+5,the remainder obtained is 0

Answer 2

Express ( 1217 )3/4 in radical form