Question

divide the product of 3 whole 1 by 2 and 1 whole 1 by 6 by sum of 1 by 3 and 1 by 4​

Answer 1

$(3 \frac{1}{2} \times 1\frac{1}{6} )\div (\frac{1}{3} + \frac{1}{4} )$

$( \frac{7}{2} \times \frac{7}{6} ) \: \div \: (\frac{4 + 3}{12} )$

$\frac{7 \times 7}{12} \times \: \frac{12}{7}$

=7

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