Math, asked by lakshmimaddi, 10 months ago

Divide the sum of 11/6 and 3/4 by their difference

Answers

Answered by ishwarsinghdhaliwal
2

Answer:

31/13

Step-by-step explanation:

Sum of 11/6 and 3/4

 \frac{11}{6}  +  \frac{3}{4}  \\  =  \frac{22 + 9}{12}  \\  =  \frac{31}{12}

Difference of 11/6 and 3/4

 \frac{11}{6}  -  \frac{3}{4}  \\  =  \frac{22 - 9}{12}  \\  \frac{13}{12}

Now,divide the sum of 11/6 and 3/4 by their difference

 \frac{31}{12}  \div  \frac{13}{12}  \\  =  \frac{31}{12}  \times  \frac{12}{13}  =  \frac{31}{13}

Answered by Anonymous
33

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so,

sum of both fraction

=\frac{11}{6}+\frac{3}{4}\\=\frac{22+9}{12}\\=\frac{31}{12}

difference of both fraction.

=\frac{11}{6}-\frac{3}{4}\\=\frac{22-9}{12}\\=\frac{13}{12}

Now,

Divide the sum and difference of both.

=\frac{31}{12}÷\frac{13}{12}\\= \frac{31}{12}×\frac{12}{13}\\=\frac{31}{13}

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