Question

Divide the sum of 12/5and13/7 by the product of -4/7 and -1/2
(Step by step)

Answer 1

Question:-

Divide the sum of $\rm{\dfrac{12}{5}}$and $\rm{\dfrac{13}{7}}$ by the product of $\rm{\dfrac{-4}{7}}$ and $\rm{\dfrac{-1}{2}}$

SOLUTION:-

Firstly,

We will find the sum and then the product in order to divide them:-

Let's do that!

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For, sum:-

$\rm{\dfrac{12}{5} + \dfrac{13}{7}}$

Lcm of 5 and 7 $\bf :\dashrightarrow{\color{magenta}{35}}$

Use formula:-

$\pink \bigstar \underline{\boxed{\tt \blue{Lcm ÷ d × n}}}$

Substituting the value, we get,

$\sf :\longmapsto{\dfrac{84 + 65}{6}}$

$\boxed{\underbrace{\bf :\implies \dfrac{149}{6}}}$

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Now, for product:-

$\rm{\dfrac{-4}{7} × \dfrac{-1}{2}}$

$\sf :\longmapsto{\cancel{\dfrac{4}{14}}}$

$\boxed{\underbrace{\bf :\implies \dfrac{2}{7}}}$

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Lastly, we have to divide the sum and product respectively

$\rm{\dfrac{149}{6} ÷ \dfrac{2}{7}}$

So,

$\sf :\longmapsto{\dfrac{\cancel{6}}{149} × \dfrac{7}{\cancel{2}}}}$

After cancelling all possibility, we get

$\sf :\longmapsto{\dfrac{\cancel{6}}{149} × \dfrac{7}{\cancel{2}}}$

Now,

$\bf :\implies{\dfrac{3}{149} × \dfrac{7}{1} = \dfrac{21}{149}}$

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Final ANSWErs:-

Sum:-

$\qquad \: \: \: \: \: \: \: \: \: \: \: \boxed{\underbrace{\bf\blue {:\implies{\dfrac{149}{6}}}}}$

Product

$\qquad \: \: \: \: \: \: \: \: \: \: \: \boxed{\underbrace{\bf\blue {:\implies{\dfrac{2}{7}}}}}$

Division [Final ones]

$\qquad \: \: \: \: \: \: \: \: \: \: \: \boxed{\underbrace{\bf\blue {:\implies{\dfrac{21}{149}}}}}$

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Answer 2

Answer:

14.9

Step-by-step explanation:

Sum of 12/5 and 13/7

= 12/5 + 13/7 = (84 + 65)/35 = 149/35 ———— 1

Product of -4/7 and -1/2

= [(-4) × (-1)]/(7 × 2) = 4/14 = 2/7 ———— 2

Dividing equation 1 by 2, we get

149/35 ÷ 2/7 = (149 × 7)/(35 × 2) = 14.9