Question

divide the sum of 13/5 and _12/7 by the product of _31/7 and 1/_2
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Answer 1

Step-by-step explanation:

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Answer 2

The Division of Sum of $\frac{13}{5}$and $\frac{12}{7}$ by the Product of $\frac{31}{7}$and $\frac{1}{2}$ is $\frac{302}{155}$

Step-by-step explanation:

Sum of $\frac{13}{5}$and $\frac{12}{7}$

$= \frac{13}{5} + \frac{12}{7}\\\\= \frac{91+60}{35}\\\\=\frac{151}{35}$

Product of $\frac{31}{7}$and $\frac{1}{2}$

$= \frac{31}{7} \times \frac{1}{2}\\=\frac{31}{14}$

Divide the Sum of $\frac{13}{5}$and $\frac{12}{7}$ by the Product of $\frac{31}{7}$and $\frac{1}{2}$

$=\frac{\frac{151}{35}}{\frac{31}{14}}\\=\frac{302}{155}$

Hence The Division of Sum of $\frac{13}{5}$and $\frac{12}{7}$ by the Product of $\frac{31}{7}$and $\frac{1}{2}$ is $\frac{302}{155}$

​#Learn more:

X+y ifx=13/4 and y=_2/7​

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