Question

divide the sum of 13/5 and -12/7 by the product of -31/7 and -1/2​

Answer 1

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

$\huge\bold{sum:}$

$= > \frac{13}{5} ( + ) - \frac{12}{7}$

$= \frac{13 \times 7 - 12 \times 5}{35}$

$= \frac{91 - 60}{35} = \frac{31}{35}$

Therefore ,sum is $\bold{ 31/35 }$

we need to divide the sum by the product of (-31/7 ×-1/2)

$= > \frac{31}{35} \div ( - \frac{31}{7} \times - \frac{1}{2} )$

$= \frac{31}{35} \div ( \frac{31}{14} )$

$= \frac{\cancel{{31}}}{35} \times \frac{14}{\cancel{{31} }} = \frac{\cancel{{14}}}{\cancel{{35} }} = {\red{ \frac{2}{5} }}$

2/5 is your answer .

Learn More :

• 2/5 is obtained is a proper Fraction
• 2/5 can also be written as 0.4
• 2/5 is a rational number as it is in the form of a p/q where q≠0.

Answer 2

Answer:

$=\frac{2}{5}$

Step-by-step explanation:

Sum of $\frac{13}{5} and \frac{-12}{7}$

$=\frac{13x7 - 12x5}{5x7}$

$=\frac{91 - 60}{5x7}$

$=\frac{31}{5x7}$

Product of $\frac{-31}{7} and \frac{-1}{2}$

$=\frac{31}{7x2}$

Dividing the two results:

$\frac{\frac{31}{5x7} }{\frac{31}{7x2} }$

$=\frac{31}{5x7} x \frac{7x2}{31}$

$=\frac{2}{5}$