Question

Divide the sum of 13/8 and -7/16by their difference​

Answer 1

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SUM =

$\frac{13}{8} + ( - \frac{7}{16} )$

$= \frac{13}{8} - \frac{7}{16}$

$= \frac{(26 - 7)}{16}$

$= \frac{19}{16}$

Difference

$\frac{13}{8} - ( - \frac{7}{16} )$

$= \frac{13}{8} + \frac{7}{16}$

$= \frac{(26 + 7)}{16}$

$= \frac{33}{16}$

Hence the required answer

$= \frac{19}{16} \div \frac{33}{16}$

$= \frac{19}{16} \times \frac{16}{33}$

$= \frac{19}{33}$

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Answer 2

Answer:

SUM =

\frac{13}{8} + ( - \frac{7}{16} )813+(−167)

= \frac{13}{8} - \frac{7}{16}=813−167

= \frac{(26 - 7)}{16}=16(26−7)

= \frac{19}{16}=1619

Difference

\frac{13}{8} - ( - \frac{7}{16} )813−(−167)

= \frac{13}{8} + \frac{7}{16}=813+167

= \frac{(26 + 7)}{16}=16(26+7)

= \frac{33}{16}=1633

Hence the required answer

= \frac{19}{16} \div \frac{33}{16}=1619÷1633

= \frac{19}{16} \times \frac{16}{33}=1619×3316

= \frac{19}{33}=3319

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