Math, asked by atharvdwivedi47, 10 months ago

Divide the sum of -3/2 and 4/7 by the product of -9/13 and -8/9​

Answers

Answered by anantrajusharma
0

Answer:

refer to the attachment

Step-by-step explanation:

JAI SHREE KRISHNA

Attachments:
Answered by Anonymous
0

\Large{\underline{\underline{\bf{Solution :}}}}

Firstly, we will add \sf{\frac{-3}{2} \: and \: \frac{4}{7}}

So, A.T.Q

\sf{→ \frac{-3}{2} + \frac{4}{7}} \\ \\ \sf{→ \frac{-21 + 8}{14}} \\ \\ \sf{→\frac{13}{14}.....(1)}

\rule{200}{1}

Now, Product of \sf{\frac{-9}{13} \: and \frac{-8}{9}}

\sf{→ \frac{-\cancel{9}}{13} \times \frac{-8}{\cancel{9}}} \\ \\ \sf{→ \frac{-(-8)}{13}} \\ \\ \sf{→ \frac{8}{13}......(2)}

\rule{200}{2}

Now, Devide equation (1) by equation (2).

\sf{→\frac{13}{14} \div \frac{8}{13}} \\ \\ \sf{→\frac{\frac{\frac{13}{14}}{8}}{13}} \\ \\ \sf{→\frac{13 \times 13}{8 \times 14}} \\ \\ \sf{→\frac{169}{112}} \\ \\ \Large{\implies{\boxed{\boxed{\sf{\frac{169}{112}}}}}}

\Large\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\sf{Jai \: Shree \: Krishna}}}}}}}}}}}}

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