Question

divide the sum of 3/49 and 7/21 by their product​

Answer 1

Answer:

1/49............ok yaar

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

$\displaystyle \: \sf{Divide \: the \: sum \: of \: \: \frac{3}{49} \: and \: \: \frac{7}{21} \: by \: their \: product}$

CALCULATION

$\displaystyle \: \sf{The\: sum \: of \: \: \frac{3}{49} \: and \: \: \frac{7}{21} }$

$= \displaystyle \: \sf{ \frac{3}{49} + \: \frac{7}{21} }$

$= \displaystyle \: \sf{ \frac{9 + 49}{147} }$

$= \displaystyle \: \sf{ \frac{58}{147} }$

$\displaystyle \: \sf{The\: product \: of \: \: \frac{3}{49} \: and \: \: \frac{7}{21} }$

$= \displaystyle \: \sf{ \frac{3}{49} \times \: \frac{7}{21} }$

$= \displaystyle \: \sf{ \frac{3}{49} \times \: \frac{7}{21} }$

$= \displaystyle \: \sf{ \frac{1}{49} }$

Hence the required result is

$= \displaystyle \: \sf{ \frac{58}{147} } \div \frac{1}{49}$

$= \displaystyle \: \sf{ \frac{58}{147} } \times \frac{49}{1}$

$= \displaystyle \: \sf{ \frac{58}{3} }$

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