Question

divide the sum of 5 by 9 and minus 8 by 7 by the product of 7 by 5 and 3 by 8​

Answer 1

Given: The sum of 5 by 9 and minus 8 by 7, the product of 7 by 5 and 3 by 8​

To find: Divide the sum of 5 by 9 and minus 8 by 7 by the product of 7 by 5 and 3 by 8​

Solution:

• Now we have given that divide the sum of 5 by 9 and minus 8 by 7 by the product of 7 by 5 and 3 by 8​ .

• Numerically it can be written as:

                { 5/9 + (-8/7) } / { 7/5 x 3/8 }

                { (35 - 72) / 63 } / { 21/40 }

                -37/63 / 21/40

                -37 x 40 /63 x 21

                -1480 / 1323

Answer:

        So the value of given term is -1480 / 1323.

Answer 2

$sum \: \: of \: \: \frac{5}{9} \: \: and \: \: \frac{ - 8}{7} \\ \\ (\frac{5}{9} ) + ( \frac{ - 8}{7}) \\ \\ \frac{5}{9} - \frac{ 8}{7} \\ \\ \frac{5 \times 7 - 8 \times 9}{63} \\ \\ \frac{35 - 72}{63} \\ \\ \frac{ - 37}{63} \\ \\ \\ product \: \: of \: \:\frac{7}{5} \: \: and \: \: \frac{3}{8} \\ \\ \frac{7}{5} \times \frac{3}{8} \\ \\ \frac{21}{40} \\ \\ \\ divison : - \\ \\ \frac{ - 37}{63} \div \frac{21}{40} \\ \\ \frac{ - 37}{63} \times \frac{40}{21} \\ \\ \frac{1480}{1323} .$