Question

divide the sum of 65/12 and 8/3 by their difference

answer this plz

Answer 1

Answer:

Divide the sum of 65/12 and 8/3 by their difference =$\frac{97}{33}$

Step-by-step explanation:

Let $A=\frac{65}{12}\: and \:</p><p>B = \frac{8}{3}$

i ) Sum =$A+B = \frac{65}{12}+\frac{8}{3}$

=$\frac{65+32}{12}$

=$\frac{97}{12}$ ---(1)

ii) Difference = $A-B=\frac{65}{12}-\frac{8}{3}$

=$\frac{65-32}{12}$

=$\frac{33}{12}$ ---(2)

According to the problem given,

$\frac{A+B}{A-B}$

= $\frac{\frac{97}{12}}{\frac{33}{12}}$

= $\frac{97}{33}$

Therefore,

Divide the sum of 65/12 and 8/3 by their difference =$\frac{97}{33}$

•••••••

Answer 2

Answer:

Answer:

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}3397

Step-by-step explanation:

Let A=\frac{65}{12}\: and \: B = \frac{8}{3}A=1265andB=38

i ) Sum =A+B = \frac{65}{12}+\frac{8}{3}A+B=1265+38

=\frac{65+32}{12}1265+32

=\frac{97}{12}1297 ---(1)

ii) Difference = A-B=\frac{65}{12}-\frac{8}{3}A−B=1265−38

=\frac{65-32}{12}1265−32

=\frac{33}{12}1233 ---(2)

According to the problem given,

\frac{A+B}{A-B}A−BA+B

= \frac{\frac{97}{12}}{\frac{33}{12}}12331297

= \frac{97}{33}3397

Therefore,

Divide the sum of 65/12 and 8/3 by their difference =\frac{97}{33}3397