find the distance of point P(2,5)from x-axis.
Answers
Answered by
89
Hey mate..
========
We know,
The equation of the points from X-axis is in the form :- y = 0
☆The distance of the point P ( 2,5) from X-axis ( abscissa ) is 5 units.☆
Hope it helps !!
========
We know,
The equation of the points from X-axis is in the form :- y = 0
☆The distance of the point P ( 2,5) from X-axis ( abscissa ) is 5 units.☆
Hope it helps !!
harry112:
thank you very much
No problem
Answered by
65
the point on x axis will have coordinate (x,0)
so given points are A( 2,5) and B(x,0)
AB = √(2-x)^2+ (5-0)^2
=√(4-4x+x^2)+ 25
=√ 4-4x+x^2+25
= √29-4x+x^2
hope it helps
please mark as brainliest
so given points are A( 2,5) and B(x,0)
AB = √(2-x)^2+ (5-0)^2
=√(4-4x+x^2)+ 25
=√ 4-4x+x^2+25
= √29-4x+x^2
hope it helps
please mark as brainliest
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