Question

divide the sum of 65/8 + 8/3 by its difference

Answer 1

Step-by-step explanation:

hope it helps you...........

Answer 2

Answer:

$sum \: of \: \frac{65}{8} \: and \: \frac{8}{3} \\ \\ = \frac{65}{8} + \frac{8}{3} \\ \\ = \frac{(65 \times 3) + (8 \times 8)}{24} \\ \\ = \frac{195 + 64}{24} \\ \\ = \frac{259}{24} \\ \\ now \: difference \: of \: \frac{65}{8} \: and \: \frac{8}{3} \\ \\ = \frac{65}{8} - \frac{8}{3} \\ \\ = \frac{(65 \times 3) - (8 \times 8)}{24} \\ \\ = \frac{195 - 65}{24} \\ \\ = \frac{131}{24} \\ \\ dividing \: \frac{sum}{difference} \\ \\ \frac{259}{24} \div \frac{131}{24} \\ \\ = \frac{259}{24} \times \frac{24}{131} \\ \\ = \frac{259}{131} \\ \\ (24 \: and \: 24 \: cancelled) \\ \\ = 1.977$

hope it helps uH ✔