Question

Divide x^2 + 4y^2 + z^2 – 4xy – 2xz + 4yz by x – 2y – z and find the quotient and remainder ..................................... please solve this anybody,

Answer 1

Step-by-step explanation:

here is your answer. good question!!

Answer 2

Answer:

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca     ----------------[ Identity ]

x² + 4y² + z² – 4xy – 2xz + 4yz = (-x + 2y + z)²

Divide x² + 4y² + z² – 4xy – 2xz + 4yz by x – 2y – z

     = (-x + 2y + z)² divided by  x – 2y – z

     = (-x + 2y + z)(-x + 2y + z) / x – 2y – z

     = (-x + 2y + z)(-x + 2y + z) / (-1)( -x + 2y + z)

     = (-x + 2y + z) / (-1)

     = x - 2y - z

Therefore , Quotient is x - 2y - z and remainder is 0.

Hope it helps you....

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