Question

divide x^3 + 3x^2 + 3x + 1 by 5 + 2x​

Answer 1

$5 + 2x \\ 5 + 2x = 0 \\ 2x = - 5 \\ x = \frac{ - 5}{2}$

${x}^{3} + {3x}^{2} + 3x + 1$

${ \binom{ - 5}{2} }^{2} + 3 { \binom{ - 5}{2} }^{2} + 3 \binom{ - 5}{2} + 1$

$= \frac{125}{8} + \frac{75}{4} - \frac{15}{2} + \frac{1}{1}$

$= \frac{ - 125 + 150 - 60 + 8}{8}$

$= \frac{ - 185 + 150 + 8}{8}$

$= \frac{ - 35 + 8}{8}$

$= \frac{ - 27}{8}$

hope it helps u...!!

Answer 2

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