Question

divide x^4-8x^3+19x^2-12x+2 by x^2-2x+2 using long division method . Please share the steps also

Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

$\mapsto\sf{p(x)={x}^{4}-8{x}^{3}+19{x}^{2}-12x+2}$

$\mapsto\tt{g(x)={x}^{2}-2x+2}$

By dividing,

$\mapsto\tt{q(x)={x}^{2}-6x+5}$

$\mapsto\tt{r(x)=10x-8}$

Now, we know remainder should be 0,

So,

$\mapsto\tt{r(x)=10x-8=0}$

$\mapsto\tt{r(x)=10x=8}$

$\mapsto\tt{r(x)=x=\dfrac{8}{10}}$

$\mapsto\huge\underline{\tt{r(x)=x=0.8}}$

Do refer the photo attached.

$\rule{200}4$

Answer 2

Answer:

Remainder => 10x - 8

Quotient => x² - 6x + 5

Step-by-step explanation:

Refer to the attachment !!